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    Aquaman43

    cool. but the “fact” about digging a hole to the middle of the earth and dropping a book down it, is incorrect. because gravity is pulling inward with the same force on all sides at once, the closer the book got to the middle, the slower it would fall, and just before it reached the bottom, it would actually stop falling and just float, never hitting bottom. fact, bitches.

    Bob

    That all depends on the air resistance, initial velocity, and what point on earth the book was dropped from, as gravity is not actually equal across the earth or within it.

    Assuming equal gravitational forces upon the book as it nears the earth’s center (about 6378 kilometers down) the book’s acceleration due to gravity would decrease, but its velocity would remain constant (excluding air resistance).

    The big wild card is the air resistance and if the air resitance changes as we get further near the center, which it most likely would increase as we get closer to the center.

    Aquaman43

    Seriously? The center of the earth is about 3900 miles deep. How much air do you think is there? You think there’s wind at the center of the earth? No way.

    Korinthian

    Another thing I heard similar to the glasses of water fact: There are more atoms in a grain of sand than there are grains of sand on earth.

    Wetwrks

    I don’t buy that about the spring and weight.

    A compressed spring should weigh the same as a non-compressed spring. They both have the same mass and that is effected the same by gravity. Try turning the spring on its side and weighing it and then compressing it (still on its side) and weighing it. It should weigh the same.

    The only way it will weigh more is if it is being pressed (compressed) against the scale and then you arn’t measuring the weight of the spring, you are measuring the weight of the spring AND the pressure necessary to compress the spring.

    Apples to oranges

    MK

    My thoughts too. If you weighed the spring and whatever is compressing it (say, a brick) together. The weight would be the same whether the brick is actively compressing it, or if they were sitting side by side on the scale.

    koko

    actually if you took physics you’d know you are wrong. the weight difference is not significant by any means, but the mathematical formula as to the weight difference is sound. you can look that up if you like.

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